How do I fix: Method 2: Using `concurrent.futures` with Timeout?

Step 1: Import the `concurrent.futures` module and define a function that takes a timeout parameter.

Coding⏱️ 2 min read📅 2026-05-31

How to Fix: Timeout on a function call

Q: Best Solutions to Fix ItMethod 1: Using the `signal` Module?

Step 1: Import the `signal` module and define a signal handler.

Timeout a Python function call with a timeout value.

Quick Answer: Use the `time` module and its `timeout` decorator to limit the execution time of your function.

📋 Table of Contents

💡 Why You Are Getting This Error
✅ Best Solutions to Fix It
💡 Conclusion

Timeout on a function call can be frustrating, especially when working with long-running operations in Python scripts. This issue often arises when a script is stuck waiting for an external process or API to complete its task.

💡 Why You Are Getting This Error

[Cause]

✅ Best Solutions to Fix It

Method 1: Using the `signal` Module

Step 1: Import the `signal` module and define a signal handler.

Method 2: Using `concurrent.futures` with Timeout

Step 1: Import the `concurrent.futures` module and define a function that takes a timeout parameter.

💡 Conclusion

To prevent your script from hanging indefinitely, you can use either of the methods outlined above. By implementing a timeout mechanism, you can ensure that your script continues executing even if a function call takes longer than expected.

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