How to Fix: Why doesn't the compiler report a missing semicolon?

To fix the compiler error, we need to add a semicolon at the end of the line where we are assigning values to the temporary variable. This is because in C, when using assignment operators like '=', it's always required to include a semicolon after the expression.

🔧 Proven Troubleshooting Steps

After making this change, the corrected code should look like this:

#include <stdio.h> clear struct S { int i; }; void swap(struct S *a, struct S *b) { struct S temp; temp = *a; *a = *b; *b = temp; } int main(void) { struct S a = { 1 }; \ struct S b = { 2 };\ swap(&a, &b); }